Question: There are 4 puppies and 3 dogs at a camp. Each dog eats twice as much food as a puppy, but each puppy eats three times as often as a dog. If a dog eats 4 pounds of food three times a day, what would be the total amount of food the dogs and puppies eat in a day? Is final answer 108?
Answer: Eating three times a day, a dog eats 3*4=<<3*4=12>>12 pounds of food.
Since there are 3 dogs at the camp, the total amount of food they eat is 3*12=<<3*12=36>>36 pounds of food in a day.
If each dog eats twice as much food as a puppy, a puppy will eat 4/2=<<4/2=2>>2 pounds of food in one meal.
Each puppy eats three times as often as a dog, and if a dog eats three times in a day, a puppy will eat 3*3= <<3*3=9>>9 times in a day.
Since a puppy eats 2 pounds of food a day, the total amount of food a puppy will eat in a day is 9*2=<<9*2=18>>18 pounds of food.
Four puppies in the camp eat 18*4=<<18*4=72>>72 pounds of food every day.
Together, the dogs and the puppies eat 72+36=<<72+36=108>>108 pounds of food in a day.
#### 108