Question: Mike and Leo have to print as many pamphlets as possible for a social gathering. Mike manages to print as fast as 600 pamphlets per hour for 9 consecutive hours. After a break, he resumes the task for another 2 hours achieving a third of the speed he was doing before. Leo, on the other hand, only works a third as many hours as Mike did before his break, but was twice as fast as Mike before he took his break. How many pamphlets do both manage to print at the end? Is final answer 9092?
Answer: Mike printed before the break 600 pamphlets per hour * 9 hours=<<600*9=5400>>5400 pamphlets
The working speed of Mike after the break was 600 pamphlets per hour / 3= <<600/3=200>>200 pamphlets per hour
Mike printed after the break 200 pamphlets per hour * 2 hours= <<200*2=400>>400 pamphlets
Leo worked third of the time that Mike worked before the break, so he worked 9 hours / 3 = <<9/3=3>>3 hours
Leo worked twice as fast as Mike before his break 600 pamphlets per hour * 2 = <<600*2=1200>>1200 pamphlets per hour
Leo printed 1200 pamphlets per hour * 3 hours = <<1200*3=3600>>3600 pamphlets
Combining the pamphlets of Leo and Mike 5400 + 400 + 3600 = <<5400+400+3600=9400>>9400 pamphlets
#### 9400