Then by the Feynman rules, the correction (from both scalars) is: Δ m H 2 = 2 × λ S 16 π 2 . {\displaystyle \Delta m_{H}^{2}=2\times {\frac {\lambda _{S}}{16\pi ^{2}}}.} (Note that the contribution here is positive.
Potom, podľa Feynmanových zákonov, korekcia (pre oba skaláre), je: Δ m H 2 = 2 ∗ λ S 16 π 2 . {\displaystyle \Delta m_{H}^{2}=2*{\frac {\lambda _{S}}{16\pi ^{2}}}.} (Všimnite si, že príspevok je tu pozitívny.