<p>Consider the typical prisoner’s dilemma,</p>

<p><span class="math-container">$$
\begin{array}{|c|c|c|}\hline
&amp;{\rm confess}&amp; {\rm lie} \\ \hline 
{\rm confess} &amp; \color{red}{-8},\color{blue}{-8} &amp; \color{red}{0},\color{blue}{-10} \\ \hline
{\rm lie} &amp; \color{red}{-10},\color{blue}{0} &amp; \color{red}{-1},\color{blue}{-1} \\ \hline
\end{array}
$$</span></p>

<p>In this case it is easy to predict that each player should play confess, regardless of the the selection made by the other player. Or in the words of the problem:</p>

<blockquote>
  <p>The best strategy (the one that outperforms other strategies) is to confess regardless of the strategy adopted by other players</p>
</blockquote>

CC BY-SA 4.0
2019-01-07T20:50:29.203Z
2019-01-07T20:50:29.203Z
caverac
<blockquote>
<p>&quot;Simple” situations (where it is easy to predict which strategies will be chosen by the different agents):</p>
<ul>
<li>Each participant has a strategy that outperforms all others regardless of the strategies adopted by its partners.</li>
</ul>
</blockquote>
<p>How can everybody have a strategy that outperforms everybody else's strategy?</p>

CC BY-SA 4.0
2019-01-07T23:30:13.460Z
The strategy outperforms all other strategies (of the player), not everybody else's.
Giskard
<game-theory>
Definition of "simple situation" is ambiguous
John
# Definition of "simple situation" is ambiguous

(Asked by: username_0 on 2019-01-07)

> "Simple” situations (where it is easy to predict which strategies will be chosen by the different agents):
>
> * Each participant has a strategy that outperforms all others regardless of the strategies adopted by its partners.

How can everybody have a strategy that outperforms everybody else's strategy?

**Tags:** game-theory

> **Comments:**
> **username_1**: The strategy outperforms all other strategies (of the player), not everybody else's.  

---

## 1 answers

### Answer by username_2 on 2019-01-07. Score: 3

Consider the typical prisoner’s dilemma,

$$
\begin{array}{|c|c|c|}\hline
&{\rm confess}& {\rm lie} \\ \hline
{\rm confess} & \color{red}{-8},\color{blue}{-8} & \color{red}{0},\color{blue}{-10} \\ \hline
{\rm lie} & \color{red}{-10},\color{blue}{0} & \color{red}{-1},\color{blue}{-1} \\ \hline
\end{array}
$$

In this case it is easy to predict that each player should play confess, regardless of the the selection made by the other player. Or in the words of the problem:

> The best strategy (the one that outperforms other strategies) is to confess regardless of the strategy adopted by other players


---

