function openURL( url ) {
	if ( !isURI( url ) ) {
		throw new TypeError( format( 'invalid argument. Must provide a valid URI. Value: `%s`.', url ) );
	}
	return window.open( url );
}
Opens a URL.

@param {string} url - URL to open
@throws {TypeError} must provide a valid URI
@returns {Window} `window` object

@example
var win = openURL( 'https://google.com' );