Q: Getting part of request url inside servlet I have an EmailVerification Servlet mapped with /ev/* url-pattern.
http://example.com/ev/ce52320570

How can I get this ce52320570 part of the URL in my Servlet?
protected void doPost(HttpServletRequest request, HttpServletResponse response)
                                                     throws ServletException, IOException {
      String vid = "";  // Here I need to get the id from the URL
}


A: Considering a Servlet (called EmailVerification) mapped to /ev/*:

Will the URL http://example.com/ev/ce52320570 trigger the EmailVerification servlet ?

Yes. In Servlet versions 2.5 and 3.0 (maybe earlier), it'll get the subpath if you map it with *, like /ev/*, as you did.

How can I get this ce52320570 part of the URL http://example.com/ev/ce52320570?



*

*request.getRequestURI() will get you the requested URL as a String, like /ev/ce52320570.

*request.getPathInfo() gets you (if exists) everything after /ev/.


*

*So in a request to /ev/123, getPathInfo() would give you /123. The same way, a request to /ev/some/other, getPathInfo() would give you /some/other.


*request.getQueryString() should be used if you need the query parameters part of the URL.


*

*Keep in mind both getRequestURI() and getPathInfo() give you only the path requested. If you need to obtain the query parameters, that is, those after the ?, like /ev/something?query1=value1&other=123, only request.getQueryString() would return the query1=value1&other=123 part.


*request.getParameter(parameterName) if you need the value of a specific query parameter.


*

*Resort to .getParameterValues() if it is a multivalued parameter




More examples of the URL parts in the request here.

A: Use request.getRequestURI() and remove what you don't need, i.e. request.getRequestURI().replace("/ev/");
